SQL ROWNUM

You should consider the order in which rows appear to be random since rows in a query result are unordered. Row order is unimportant for table operations, according to the relational paradigm, which gives rise to this predicament. The ORDER BY clause is always the last clause in a SELECT statement. In this situation, you can use it to sort results by a particular column or columns in either ascending (lowest to highest) or descending (highest to lowest) order.

You can use the NULLS FIRST or NULLS LAST options to specify the order of NULL values. In contrast to NULLS LAST, which inserts NULL values after other non-NULL values, NULLS FIRST places NULL values before other non-NULL values.

Syntax:

The following shows the syntax of the ORDER BY clause:

ORDER BY sort_expression1 [,sort_expression2, ...] 
[ASC | DESC] 
[NULLS FIRST | LAST]

To sort by a column:

SELECT columns
  FROM table
  ORDER BY sort_column [ASC | DESC];

columns denotes one or more column names separated by commas, sort column denotes the column used to order the results, and table denotes the table is a collection columns and sort column. (sort column need not be included in the list of columns.) For an ascending sort, enter ASC, and for a descending sort, enter DESC.

Example 1: Since the refrigerator is the most expensive item in category 1, its row number is 1. TV is in category 2 and is a different division or group for the ROW NUMBER function, therefore it too has a row number of 1. Since the couch is under category 2 and follows the television, its row number is 2.

By modifying the ORDER BY clause at the end of the query, we can alter the presentation order of the data without affecting how the row number is determined.

SELECT product_name,
product_category_id,
price,
ROW_NUMBER() OVER (
  PARTITION BY product_category_id
  ORDER BY price DESC
) AS rownum
FROM dbo.product
ORDER BY product_category_id ASC, price DESC;

Example 2: A "basic" row number is typically all that is needed when a row number is wanted. I refer to this as a "basic row number" because it merely generates a row number based on one result set column and is PARTITION BY clause-free. The "ColID" column will be used in the first illustration to generate a row number. To specify how the row number is assigned, a "ASC" or "DESC" (sort ASCending or DESCinding) can be appended to the ORDER BY clause; otherwise, ASCending is used by default.

SELECT  ColID
       ,ColValue
       ,ROW_NUMBER() OVER(ORDER BY ColID) AS [New_Row_Number]
  FROM dbo.TableOne;
GO

Example: The_row number() window function in Postgres and Redshift databases can be used to create a unique column if you encounter this problem with a derived table. Then, you may utilize this field as a main key:

view: derived_table_name {
  derived_table {
    sql:
    SELECT
    row_number() OVER(ORDER BY created_at) AS prim_key,
    *
    FROM orders ;;
  }

  dimension: prim_key {
    type: number
    primary_key: yes
    sql: ${TABLE}.prim_key ;;
  }
}

An ORDER BY clause is required in the window function's OVER clause (Databricks SQL). Row number, as opposed to rank and dense rank, breaks ties.

The result is non-deterministic if the order is not distinct.

Example:

SELECT a,
      b,
      dense_rank() OVER(PARTITION BY a ORDER BY b),
      rank() OVER(PARTITION BY a ORDER BY b),
      row_number() OVER(PARTITION BY a ORDER BY b)
    FROM VALUES ('A1', 2), ('A1', 1), ('A2', 3), ('A1', 1) tab(a, b);

The COUNT function. Set the Dognition database as the default after loading the SQL library.

An analytical function is ROWNUMBER. Each row to which it is applied, whether each row in the partition or each row returned by, receives a special number.

Since row number() can be used to determine that, count() wouldn't extend the query's execution time.

Example: Despite the table's repeated Seq Scan, it turns out that calculating the count() with a scalar subquery is quicker:

select row_number() over (order by foo_date) as rn,
  (select count(*) from foo) as total_count, 
  f.* 
from foo f

Of all the clauses, DISTINCT is evaluated last or nearly last. As a result, it cannot be utilised at the same level as ROW NUMBER to provide the desired outcomes.

I need to number the rows and have a distinct query that returns as a single concatenated string (it needs to be put into a system that expects a fixed-length field dependent on position). Despite trying a variety of different row-numbering techniques, I still end up with the result that all the rows are numbered before the distinct condition of the select is implemented. Because there are 91 rows instead of 13, I am surprised to see them instead of the expected 13 rows. I need the rows 1 through 13 labeled.

distinct row_numberselect

DISTINCT is processed after ROW_NUMBER which creates unique values :-)

You need to move the DISTINCT into a Derived Table:

SELECT ROW_NUMBER(....), dt.*
FROM
  ( SELECT DISTINCT ... FROM ...) AS dt

Example: Either use a derived table with DISTINCT:

SELECT
  Dept
FROM (
  SELECT
    Dept,
    ROW_NUMBER() OVER (ORDER BY Dept) AS RowID
  FROM (
    SELECT DISTINCT
      Dept
    FROM Department
    WHERE Dept ... 
  ) AS d
) AS Calls
WHERE RowID ...
;

The ROW_NUMBER() function assigns ranks to duplicate rows by returning the sequential number for each row inside its partition, starting from 1 to the number of rows in the partition.

Example 1: Seeing the duplicates & triplicates is the query below where Row_Number() Over() has been used with the Partition By clause. The Row_Number() Over() function is looking for rows with the same values of Emp_Name, Company, Join_Date and Resigned_Date columns in the Emp_Details table. The first occurrence of this combination of columns is being allocated a RowNumber of 1. The subsequent occurrences of the same combination of data are being allocated RowNumber of 2, 3 and so on. When a new combination of Emp_Name, Company, Join_Date and Resigned_Date columns is encountered, that set is treated as a new partition and the RowNumber starts from 1 again thanks to the Partition By clause. In essence, the columns in the Partition By clause are being grouped together as per the Partition BY clause and then ordered using the Order By clause:

select Emp_Name
      ,Company
      ,Join_Date
      ,Resigned_Date
      ,ROW_NUMBER() over (partition by Emp_Name, Company, Join_Date
                         ,Resigned_Date
                          order by Emp_Name, Company, Join_Date
                         ,Resigned_Date) RowNumber 
from Emp_Details

Output:

In the result set above, a duplicate row exists everywhere the column RowNumber is bigger than 1. As an illustration, the first row with RowNumber 1 and the second row with RowNumber 2 in the result set above are identical. Similar to the third row with a row number of 1, the fifth row with a row number of three and the fourth row with a row number of two are duplicates and triplicates of the third row, correspondingly.

Example 2: Based upon that rank, we can delete that row from the table.

For this demonstration, consider the following example given below.

DELETE duplicate_records
FROM
(
SELECT *, DupRank = ROW_NUMBER() OVER(
              PARTITION BY first_name, last_name, email, Country
              ORDER BY (SELECT NULL) )
FROM SampleTable
) AS duplicate_records
WHERE DupRank > 1 

The Row Number() method is used in the instance above to rank each duplicate row in the sample table. The DELETE statement is then used to remove any records where the rank is greater than 1.

Since the sample table in our case contained a total of 4 duplicate records, the query will remove those 4 records from the table.

Example 3: The sentence below uses the ROW_NUMBER() function to assign a sequential number to each row. This query will allocate a row number larger than one if it discovers a name column of the table duplicate.

SELECT id, name, ROW_NUMBER()   
OVER (PARTITION BY name ORDER BY name) AS row_num   
FROM student_contacts;  

We can now remove the duplicate records from the student_contacts table with the help of the DELETE statement and a subquery in the WHERE clause. See the below statement:

DELETE FROM student_contacts WHERE id IN(  
    SELECT id FROM (SELECT id, ROW_NUMBER()   
       OVER (PARTITION BY name ORDER BY name) AS row_num   
    FROM student_contacts) AS temp_table WHERE row_num>1  
);

After the statement has been executed, we will receive the output shown in the below image, in which we can see that five records have been deleted from the table. The SELECT command can be used to check whether duplicate rows were eliminated or not.

A row number is added to each group using the ROW_NUMBER() OVER(PARITION BY...) capability, and it is reset for each subsequent group.

Each row in the result set is given a sequential row number by the window function row_number() in the MySQL database. The first row in the numbering is 1. Your table or query result can be divided into various groups, with each group being given a unique row number. In this instance, each group's initial row number will begin with 1.

Create a CTE in which you give each row within each group a number. The ROW_NUMBER() function can be used to accomplish that. You can define the order in which the numbers should be given to the rows in OVER() as well as the groups into which the rows should be separated (PARTITION BY) (ORDER BY).

Here is the syntax of row_number() function.

ROW_NUMBER() OVER (
   PARTITION BY <expression>,[{,<expression>}...]
   ORDER BY <expression> [ASC|DESC],[{,<expression>}...]
)

In the above statement, PARTITION BY partitions the table or result set into smaller groups. The expression for PARTITION BY would be one or more expressions used in GROUP BY clause of SQL query. Please note, PARTITION BY clause is optional.

Example: Take a look at the result of the inner query:

SELECT *,
  ROW_NUMBER() OVER(PARTITION BY year ORDER BY result DESC) AS row_number
FROM exam_results;

You give each group's rows a row number (i.e., year). Based on the value of the result column, a row number is assigned to each row. The DESC keyword following the ORDER BY result causes the rows to be sorted in descending order. The rows are assigned separate numbers even if more than one row in a group has the same value of the result. However, Emily Kelly and Edith Black have distinct row numbers while having the same outcome. Use RANK() or DENSE_RANK() in place of ROW_NUMBER() to alter this behaviour and assign the same row number for the same result within a group.

When using SQL Server for paging, the Row_Number function is crucial. For each partition indicated in the OVER clause, the Row_Number function is used to provide sequential numbering of the rows in the result by the order chosen in the OVER clause. The number of succeeding rows will be increased after assigning the value 1 to the first row.

The ROW_NUMBER determines the temporary value when the query is executed. If you want to get the numbers in a table, you need to see the IDENTITY property and SEQUENCE. When the ROW_NUMBER function in SQL Server encounters two identical values in the same partition, it assigns different rank numbers to them. The rank number will be determined by the order in which they are displayed.

Syntax:

ROW_NUMBER ()
OVER ([PARTITION BY value_exp, ... [ n ]] order_by_clause [ASC | DESC], ...)

• OVER - Specify the order of the rows.
• ORDER BY - Provide sort order for the records.
• The ROW_NUMBER function enumerates the rows in the sort order defined in the over clause.

Example 1: The following statement finds the first name, last name, and salary of all employees. In addition, it uses the ROW_NUMBER() function to add sequential integer number to each row.

SELECT 
    ROW_NUMBER() OVER (
            ORDER BY salary
    ) row_num, 
    first_name, 
    last_name, 
    salary
FROM
    employees;

Example 2: The following row_number in SQL Server query will partition the data by Occupation and assign the row number using the yearly income.

SELECT [FirstName]
      ,[LastName]
      ,[Education]
      ,[Occupation]
      ,[YearlyIncome]
      ,ROW_NUMBER() OVER (
                     PARTITION BY [Occupation] 
                     ORDER BY [YearlyIncome] DESC
             ) AS [ROW NUMBER]
  FROM [Customers]

Example: The following example generates the average price for each item group in Postgresql when group by clause is applied to sets of rows.

SELECT item_groups.item_group_name,
	AVG (item_price)
FROM
	items
INNER JOIN item_groups USING (item_group_id)
GROUP BY
	item_group_name;

As we can see from the above output, we have inner joined the table item_group, and items using item_group_id column then applied aggregate function (Average function) on item_price, and grouped by item_group_name.

Example 1: To get the max(ROW_NUMBER()) --> Or I guess this would also be the count of all rows:

I tried doing:

SELECT max(ROW_NUMBER() OVER(ORDER BY UserId)) FROM Users

but it didn't seem to work...

To get ROW_NUMBER() using a given piece of information, ie. if I have a name and I want to know what row the name came from.

Example 2: The combination of the Dept_Id and Dept_Split fields will become the group for continuous rows. Now use group by on these fields and find the min and max values. The final SQL query is:

SELECT  Dept_Id,
        MIN(Emp_Seq) Min_Seq,
        MAX(Emp_Seq) Max_Seq
FROM
(
SELECT  Dept_Id,
        Emp_Seq,
 Emp_Seq-ROW_NUMBER() OVER (PARTITION BY Dept_Id ORDER BY Emp_Seq) Dept_Split
FROM    employees;
) A
Group BY Dept_Id, Dept_Split

Oracle's rownum pseudocolumn can be replaced with row_number() over (order by null).

• ORDER BY: Establishes the foundation for ranking. To break any ties in the order, you can add more ORDER BY clauses.
• expression: gives the values that will be the foundation for the rankings.
• DESC | ASC: Sorts the rating either from largest to smallest (descending) or from smallest to largest (descending).
• NULLS {FIRST | LAST}: Specifies whether members with null values should appear first or last in the list.
• order_by_clause::= :expression [ASC | DESC] [NULLS {FIRST | LAST}]

Example 1: Canonical way to do this is the following: ROW_NUMBER() OVER(ORDER BY (SELECT NULL)). If you're golfing, you might try something like this:

SELECT value, n = ROW_NUMBER() OVER(ORDER BY (SELECT 1))
FROM STRING_SPLIT('one,two,three,four,five',',')

Example 2: There must be a window order clause, and SQL Server prohibits ordering that is based on a constant, such as ORDER BY NULL. But interestingly, SQL Server will accept expressions that are passed that are predicated on a subquery that returns a constant, such ORDER BY (SELECT NULL). The optimizer simultaneously un-nests, or expands, the phrase and notices that the ordering is constant across all rows. As a result, it no longer requires the input data to be ordered. Here is an example query using this method in its entirety:

SELECT actid, tranid, val,
 ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) AS rownum
FROM dbo.Transactions;

Example 3: I'm trying this because some queries are very slow when paginated with rownum (compared with row_number()) and I can't simply move the order by clause into row_number():

It does in the sense that we don't need to really do a sort, eg,

select row_number() over (order by null) as rnum, i.* 
from invoice i 

Statistics

Each partition receives a separate application of the Row_Number() function, and the row number for each partition is reset.

The PARTITION BY phrase partitions the window into more manageable sets. If the PARTITION BY clause is used, each partition's row number begins with one and increases by one.

In order to describe the partitioning and ordering of records prior to the ranking functions being evaluated, the OVER clause is a must in all ranking functions. You will receive an error similar to "Incorrect syntax near 'ROW_NUMBER', intended 'OVER'" if you don't supply it.

PARTITION BY is not necessary. When there is no PARTITION BY or RESET WHEN clause, the full result set as provided by the ORDER BY clause acts as a partition.

Example 1: The following sentence uses the ROW_NUMBER() function to allocate a sequence number to each record inside a partition.

SELECT *,   
    ROW_NUMBER() OVER(PARTITION BY Year) AS row_num  
FROM Person;  

Example 2: To order salespersons based on sales within a sales region, the following SQL query might yield the following results.

SELECT ROW_NUMBER() OVER (PARTITION BY sales_region 
     ORDER BY sales_amount DESC),
sales_person, sales_region, sales_amount
FROM sales_table;

Output:

Example 3: Because we did not use the PARTITION BY clause, the ROW_NUMBER() function considers the whole result set as a partition.

SELECT product_id,
	product_name,
	group_id,
	ROW_NUMBER () OVER (
		PARTITION BY group_id
	)
FROM
	products;

Selecting a random sample of rows organised by a column using random sorting.

For each user_id, generate a random row number that resets for each of my periods or groups. This is accomplished by utilizing the random() method to order the row_number() function. Although random() can be parameterized with a seed, it seems to me that this only yields repeatable results if your function is only run on one node given the concurrent nature of data warehouse solutions like Snowflake and Redshift (like the leader node).

Using our new random row number as a filter, choose N of those rows.

Example 1:

with randomly_sorted_users as (

    select
        user_id,
        signup_date,
        row_number() over(partition by date_trunc('year', signup_date)
                            order by random()) as random_sort
    from
        user_table

)
select
    user_id,
    signup_date
from
    randomly_sorted_users
where
    random_sort <= 5

This will yield 10 rows in total, 5 chosen randomly by signup year:

Results:

| #  | user_id                          | signup_date |
|----|----------------------------------|-------------|
| 1  | e58975cdb6f4b052389b199f623319dd | 2017-10-15  |
| 2  | c7253ee384f5be436fef0b900c9e5125 | 2017-05-03  |
| 3  | 1400ffe327b1b15130fe85535eee58ba | 2017-03-05  |
| 4  | 1079a421f9a59e1716082424310f6dc0 | 2017-12-15  |
| 5  | f4fed873df3786d04cdef1ccce59eb36 | 2017-02-21  |
| 6  | db3a60a5d55fc8a4aa20f5d8a2f276af | 2018-01-25  |
| 7  | 9e991194118d3e4db471106358825685 | 2018-04-11  |
| 8  | 008a3b0f05c601ea39f0e893d4e11043 | 2018-02-09  |
| 9  | 7e40c4cce72ae34ca0e6e4e39efdb514 | 2018-03-04  |
| 10 | 1b9d2c64344629aebf2349d328e76aae | 2018-06-30  |

Example 2: The newid function, which creates a unique value for each row each time a query is conducted, is used as sorting in the row number function, which allocates a row_number based on aggregate or sorting:

select row_number() over(order by newid()) as randomico1,
       row_number() over(order by newid()) as randomico2,
       ra
  from saluno
 order by ra

The window function ROW_NUMER() is frequently used to return a row's sequential number within each partition of a result set, counting up from 1 for each partition. Those figures are only present in the query results, not in the table.

In other words, you are assigning numbers to the search's results. The output number of ROW_NUMBER is sequential, as opposed to RANK, which gives each row in a group a fixed value and leaves a space between the group records.

Syntax:

General syntax for ROW_NUMBER():

ROW_NUMBER ( )   
    OVER ( [ PARTITION BY column_1 , ... [ n ] ] ORDER BY column_2 )  

PARTITION BY argument is optional.

When you include this argument, the function will separate the outcomes into various sets and organize them according to the value from the column col_1. There will be various sets of row numbers for each set of results.

If we have three sets of results, for instance, the function will first number the first set of results before starting over for the second set and then starting over once more for the third set.

The ROW_NUMBER function will handle all rows from the query result as a single group if PARTITION BY is not given.

col_1 is another option for the ORDER BY clause.

Example 1: ROW_NUMBER(): return a number with each row in a group, starting at 1:

SELECT prd_type_id, 
SUM(amount),
 ROW_NUMBER() OVER (ORDER BY SUM(amount) DESC) AS row_number
FROM all_sales
    GROUP BY prd_type_id
    ORDER BY prd_type_id;

>Output:

Example 1: The ROW_NUMBER function can be used in place of TOP clauses and aids in assigning temporary numbers to the query's result set. The first four rows of the Product table, for instance, will be returned with the following query.

SELECT * FROM (
SELECT Name, 
        ProductNumber, 
        StandardCost,
        ROW_NUMBER() OVER (ORDER BY StandardCost DESC) AS RN
FROM Production.Product
) AS TMP_TBL
WHERE RN<=4;

The SQL SELECT TOP statements have been discussed in this article; this query structure aids in limiting the result set of queries. At the same time, we have discovered some TOP clause replacements.

Example 2: The third query utilizes the ROW_NUMBER() analytical function to provide ranks using the OVER function. The RANK function and DENSE_RANK can both be used to retrieve the TOP N records starting with Oracle 9i and later.

select Ten_Most_Expensive_Products, Unit_Price
from
(
    select distinct Product_Name as Ten_Most_Expensive_Products, 
           Unit_Price,
           ROW_NUMBER() over (order by Unit_Price desc) row_number
    from Products
    order by Unit_Price desc
)
where row_number between 1 and 10;

The row's position is returned by ROW_NUMBER. Even with duplicate rows, the row_number() function always produces a unique rating.

The difference between RANK() and ROW_NUMBER() is that "equal" rows are rated equally. Depending on its position, RANK outputs the rank of the row.

Example 1: While the RANK function will assign the same priority to the same rows, ROW_NUMBER will deploy the numbers in a serial fashion to the result set. The generic ranking function is similar to RANK. If two people tie for second place, the following person will be given fourth place because the ranking principle will ignore third place.

The salaries of the two workers in the table are the same. As a result, when sorted by the salary column, all three functions RANK, DENSE RANK, and ROW NUMBER produce a rising integer value.

SELECT Name, Salary, Gender,
ROW_NUMBER() OVER (ORDER BY Salary DESC) AS RowNumber,
RANK() OVER (ORDER BY Salary DESC) AS [Rank],
DENSE_RANK() OVER (ORDER BY Salary DESC) AS DenseRank
FROM Employees;

Example 2: Here in the example rank behaves like rownumber and rank return position of row:

SELECT *, ROW_NUMBER() OVER(order by Col) as [ROW_NUMBER]
,RANK() OVER(ORDER BY Col) as [RANK]
,DENSE_RANK() OVER(ORDER BY Col) as [DENSE_RANK]
FROM (  VALUES('a'),('a'),('a'),('b'),('c'),('c'),('d'),('e') ) Tab(Col)

Example 3: In Postgresql, Row_number( ) function assigns a unique integer to each row sequentially or returns the row number for each group on the basis of Partition By.

Let’s understand it by example.

SELECT item_groups.item_group_name,
item_name,
ROW_NUMBER () OVER (PARTITION BY items.item_group_id)
FROM items
JOIN item_groups ON item_groups.item_group_id=items.item_group_id;

We have joined the two tables item_groups and items on item_group_id, then Partition By items.item_group_id.

It has been partitioned into smaller subsets like Smartphone, Laptop, Tablet, and Row_number( ) function assigned unique integer to each row sequentially within the smaller subsets.

Rank( ) assigns the same integer value for ties like ( 1,2,2,3 ).

SELECT item_groups.item_group_name,
	item_name,
	RANK () OVER (PARTITION BY item_groups.item_group_name)
FROM items
   JOIN item_groups ON item_groups.item_group_id=items.item_group_id;

This time result is different from Row_number( ) function, rank provided the same value for each partitioned.

Example 1: The result set from the Row_number() function will be filtered using the WHERE clause in Postgresql, and it will also be divided by item_id.

SELECT item_id,
	item_name,
	item_group_id,
	ROW_NUMBER () OVER (PARTITION BY item_id)
FROM
	items
	WHERE item_group_id =1;

The item name (Nokia, HTC, Nexus, and iPhone) that belongs to item_group_id is displayed as a result of our WHERE clause filtering the result set using item_group_id(1).

Example 2: We must first utilise the ROW_NUMBER() function in a subquery or a common expression table (CTE) because it is a windows function that assigns row numbers after the WHERE clause filtering is complete. This is necessary for utilising row number in the WHERE clause of a SQL query. To demonstrate the same in this example, a CTE was developed. To further show the same in the following example, we will use a subquery.

WITH CTE AS (
SELECT year,
salesperson,
sale_amount,
store_state,
ROW_NUMBER ()
OVER (PARTITION BY year ORDER BY sale_amount DESC) as row_number
FROM
yearly_sales )
SELECT year, salesperson
FROM CTE
WHERE row_number = 1;

Example 3: The code problem you are looking for is "SQL Row Number() function in Where Clause", we have come up with a better solution from many answers. Below is a description of such solution. Please get in touch with us if this sql programming code does not resolve the issue.

SELECT  employee_id
FROM    (
        SELECT  employee_id, ROW_NUMBER() OVER (ORDER BY employee_id) AS rn
        FROM    V_EMPLOYEE
        ) q
WHERE   rn > 0
ORDER BY
        Employee_ID

Note that this filter is redundant: ROW_NUMBER() starts from 1 and is always greater than 0.

The select query's result set's consecutive row numbers are created using the ROW_NUMBER() function. To produce row numbers, you must combine the ORDER BY clause with ROW_NUMBER(). in possible to allocate the numbers to the correct sequence.

To guarantee that the numbers are allocated to the correct order, define the ORDER BY clause using the Row_Number() function.

Example 1: Typically, ROW_NUMBER() and ORDER BY can be used together, as in the instance below.

If you attempt to use ROW_NUMBER() without an ORDER BY clause, you will see the following error.

SELECT
    ROW_NUMBER() OVER() AS Row_Num, 
    Employee_Name 
    FROM MTB_Table_A
GO

Result:

The function 'ROW_NUMBER' must have an OVER clause with ORDER BY.

Example 2: In Postgresql, we use the PARTITION BY clause to divide the window into smaller subsets based on the values in the item_id column, use the below query.

SELECT item_id,
	item_name,
	item_group_id,
	ROW_NUMBER () OVER (PARTITION BY item_id)
FROM
	items;

The ROW_NUMBER() method in this situation assigns one to the first row of each smaller set or partition and increases by one for the following row in the same partition.

Example 3: Generate row number without using any column in ORDER BY clause.

SELECT *,ROW_NUMBER() OVER () AS SNO FROM #TEST

Example 4: Add row number in my existing query so that I can track how much data has been added into Redis. If my query failed so I can start from that row no which is updated in other table.

Query to get data start after 1000 row from table:

SELECT * 
FROM (SELECT *, ROW_NUMBER() OVER (Order by (select 1)) as rn ) as X where rn > 1000

Query is working fine. If any way that I can get the row no without using order by.

Example 5: However, if we want the row numbers to be constructed in the same sequence as the data is submitted, there is a method. Instead of utilizing the column name in the ORDER BY clause for this implementation, we can use any literal value.

SELECT *, ROW_NUMBER() OVER(ORDER BY (SELECT 100)) AS Row_Number 
from Employee  

Instead of specifying any column name with an Order By clause in the aforementioned query, we are utilizing the "SELECT 100" statement. The Row Number column will now be added to the query without any table values being ordered.

To create a serial number for a given recordset in SQL Server 2019/2017, use the Row_Number() function. But in order to guarantee that the numbers are assigned to the right sequence, we must always utilize the ORDER BY clause with the Row_Number function.

Example 1: Now, the OVER clause must always be used with the Order By argument, and if the OVER clause is missing when using Row_Number, the SQL Server will give an error.

SELECT *, ROW_NUMBER() AS Row_Number 
from Employee 

Because we did not utilize the OVER clause with the Row_number() function in the code above, when we try to run it, the following error is returned.

MySQL's ROW NUMBER function can be used without the PARTITION BY Clause. As we just discussed, the ROW_NUMBER function will treat the entire result set as a single partition if we did not provide the PARTITION BY Clause in MySQL. As a result, based on the column(s) supplied in the order by clause, the ROW_NUMBER function will produce a sequential numbering for each row contained in the result set.

Syntax:

ROW_NUMBER() OVER (ORDER BY Col1, Col2)

Example 1: Use ROW_NUMBER which requires the OVER clause without either the PARTITION BY or the ORDER BY parts. So let’s try that out.

-- Create a table to test with
CREATE TABLE Windowing (col1 int, col2 int);
INSERT INTO Windowing 
    VALUES (1,1), (1,2), (1,3), (1,4), (1,5)
        ,(2,6), (2,7), (2,8), (2,9), (2,10);
GO

-- Test ROW_NUMBER without PARTITION BY or ORDER BY

SELECT ROW_NUMBER() OVER (), *
FROM Windowing;

Example 2: Used the MySQL ROW_NUMBER function without using the PARTITION BY clause.

SELECT Id, Name, Department, Salary,
ROW_NUMBER() OVER (ORDER BY Department) AS RowNumber
FROM Employees;

You will receive the following output after running the aforementioned query. You can see from the result below that there is no partition and that all of the rows have sequential numbers allocated to them starting from 1 to 12 depending on the Department column.

Example 3: Since the data in this example is not partitioned, ROW_NUMBER will number every row in the table sequentially according to the constraints given by the ORDER BY clause.

SELECT Name, Gender, Salary,
        ROW_NUMBER() OVER (ORDER BY Gender) AS RowNumber
FROM Employees

Please note: If ORDER BY clause is not specified you will get the following error.

The function 'ROW_NUMBER' must have an OVER clause with ORDER BY.